Golden Section for an 8.5" x 11" horz paper...

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Kyle Hildebrant's picture
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Joined: 7 Jan 2003 - 11:00am
Golden Section for an 8.5" x 11" horz paper...
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So Im trying ti fugure out what the golden section for an 8.5” x 11” USA letter sized paper would be. I know how one would figure this out for a square, but what about something not square? how would I go about this?


hildebrant.

Nathan Matteson's picture
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Joined: 16 Dec 2002 - 11:00am
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As far as know, Kyle, that would be impossible. The golden section is generally approximated by the ratio 1:1.618. Which, sadly for us, isn’t a US letter sheet. Unless you trim it.

Nate

seanmichael's picture
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Joined: 16 Dec 2002 - 11:00am
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Here you are Kyle.





-smc

Kyle Hildebrant's picture
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Joined: 7 Jan 2003 - 11:00am
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sweet, I looks like it matches the design I did.

hildebrant.

seanmichael's picture
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Joined: 16 Dec 2002 - 11:00am
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wow. votes.

seanmichael's picture
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Joined: 16 Dec 2002 - 11:00am
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Can we see your design?

-smc

Kyle Hildebrant's picture
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Joined: 7 Jan 2003 - 11:00am
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I hate our paper sizes :-(…. but still is it not possible to find these in a non square size? or am I crazy?

Nathan Matteson's picture
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Joined: 16 Dec 2002 - 11:00am
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US paper sucks. Why is it that we don’t use metric? Anyway, after some fast long division, it seems that the closest (cheapest and easiest) you can get with US letter is to trim it to 11 x 6 13/16. That might be a resonable Golden Section.

Nathan Matteson's picture
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Joined: 16 Dec 2002 - 11:00am
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One more approximation (based on the Fibonacci series) would be 233mm x 144mm.

Rodolfo Capeto's picture
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Joined: 5 Aug 2002 - 1:27pm
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Kyle, I don’t understand what you want to do (didn’t get what
you mean by

Nathan Matteson's picture
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Joined: 16 Dec 2002 - 11:00am
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OK, so I forgot about this thread, but today while I was teaching I farted out a way to geometrically derive a golden section from ugly US paper. Take an 11x17 sheet. Assume you’re looking at it vertically. Draw a horizontal line 11” from the bottom to describe an 11” square. Draw a horiz. line 5.5” from the bottom to bisect the square. Draw a diagonal line from the bottom left corner to the top right corner of the lower half of the square. Rotate that line counterclockwise so that its arc hits the left edge of the paper approximately 12.3” from the bottom. Draw a horizontal line from that point. The area bounded by that line, the line at 5.5”, and the left and right edges of the sheet should be a Golden Rectangle.

Although it would still be easier to trim your paper to 11 x 6 13/16”. That’s essentially what you’ve just constructed. And with a lot less waste.

Kyle Hildebrant's picture
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Joined: 7 Jan 2003 - 11:00am
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how about 9” x 12” :-)


hildebrant.

being that this is what my specs have changed to. :-)

seanmichael's picture
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Joined: 16 Dec 2002 - 11:00am
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You ratio is 3 to 4.





Use #3 if you can.

-smc

Kyle Hildebrant's picture
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Joined: 7 Jan 2003 - 11:00am
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how about for horizontal orientation?